Tugas II operation

Name: Chea Lida
Major: TMD

Define the calculation operations below. Make analysis / explanation in the form of
comments in the code.

1
#include<stdio.h>
#include<stdlib.h>

int main(void)
{
    int i=8,j=5,k;// declare variable
    k=(3*i-2*j)%(2*j-4);

    /*it calculate value in peranthesis first and
    multiplicate symbol * is a symbol for calculate first and
    then subtract
    k=(3*i-2*j)%(2*j-4)
    =((3*8)-(2*5))%((2*5)-4)
    =(24-10)%(10-4)
    =14%6
    =2
    */

    printf("k=(3*i-2*j)%(2*j-4)= %d \n",k); //
    system("pause");
    return(0);
}

2
include<stdio.h>
#include<stdlib.h>

int main(void)
{
    int i=8,j=5,k;// declare variable
    k=-(i + j ) ;
    printf("k=-(i + j )= %d \n",k);
        /*k=-(i + j )
           =>-(i+j)=-i-j
           =-8-5
           =-13*/
    system("pause");
    return(0);
}

3
#include<stdio.h>
#include<stdlib.h>

int main(void)
{
    int i=8;// declare variable
    for(i;i<10;i++){
    printf("k= %d \n",i);
    /*mean that i catch declared value first then take declared
    value add 1 until finish condition*/
   
    }
    system("pause");
    return(0);
}
4
#include<stdio.h>
#include<stdlib.h>

int main(void)
{
    int i=8;// declare variable
    for(i;i<10;++i){
    printf("k= %d \n",++i);
    /*mean that i catch the value i=8 add 1 until finish condition
    i=i+1
    */
   
    }
    system("pause");
    return(0);
}
5
int main(void)
{
    float x=0.005;// declare variable
    printf("x=%f \n",++x);
    //mean that x catch declared value add 1
   
    system("pause");
    return(0);
}

6
#include<stdio.h>
#include<stdlib.h>

int main(void)
{
    int i=8,j=5,k;// declare variable
    k=(i > 0)|| (j < 5);
    printf("i or j ( 1 = true, 0 = false):%d\n",k);
    /*if which is ture mean that true =1 but both of it false mean
    that false =0*/
   
    system("pause");
    return(0);
}
 7
#include<stdio.h>
#include<stdlib.h>

int main(void)
{
    float x=0.005, z;// declare variable
    z = ( x >= 0) ? x : 0;
    //if it true z=x and false = 0
    printf("if true=0.005 and wrong= 0 \n=%f\n",z);
    system("pause");
    return(0);
}

8
#include<stdio.h>
#include<stdlib.h>

int main(void)
{   
    int i=8,j=5,k;// declare variable
    k= (i + j );
    //i=8 and j=5 =>8+5=13
    printf("k = (i + j ):%d\n",k);
    system("pause");
    return(0);
}

9
#include<stdio.h>
#include<stdlib.h>

int main(void)
{

    float x=0.005,y=-0.01, z;// declare variable
    z = (2 * x + y) == 0;
    printf("if true =1 false=0\n=%.f\n",z);
    /*z=0  because operation in (2 * x + y)  symbol multiplicate do
     first so 2*0.005+(-0.01)=0 is true*/
    system("pause");
    return(0);
}

10

#include<stdio.h>
#include<stdlib.h>

int main(void)
{
    int i=8,j=5,k;// declare variable
    k=(i > 0)|| (j < 5);
    printf("i or j ( 1 = true, 0 = false):%d\n",k);
    /*if which is ture mean that true =1 but both of it
     false mean that false =0*/
   
    system("pause");
    return(0);
}

 

http://www.youtube.com/watch?v=Am1EVdKfgko&feature=youtu.be